3(c-6)=27

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Solution for 3(c-6)=27 equation: 



3(c-6)=27

We move all terms to the left:

3(c-6)-(27)=0

We multiply parentheses

3c-18-27=0

We add all the numbers together, and all the variables

3c-45=0

We move all terms containing c to the left, all other terms to the right

3c=45

c=45/3

c=15

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