4(3y-1)=7(3-y)

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Solution for 4(3y-1)=7(3-y) equation: 



4(3y-1)=7(3-y)

We move all terms to the left:

4(3y-1)-(7(3-y))=0

We add all the numbers together, and all the variables

4(3y-1)-(7(-1y+3))=0

We multiply parentheses

12y-(7(-1y+3))-4=0



We calculate terms in parentheses: -(7(-1y+3)), so:

7(-1y+3)

We multiply parentheses

-7y+21

Back to the equation:

-(-7y+21)



We get rid of parentheses

12y+7y-21-4=0

We add all the numbers together, and all the variables

19y-25=0

We move all terms containing y to the left, all other terms to the right

19y=25

y=25/19

y=1+6/19

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