3(c-3)=7c-2

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Solution for 3(c-3)=7c-2 equation: 



3(c-3)=7c-2

We move all terms to the left:

3(c-3)-(7c-2)=0

We multiply parentheses

3c-(7c-2)-9=0

We get rid of parentheses

3c-7c+2-9=0

We add all the numbers together, and all the variables

-4c-7=0

We move all terms containing c to the left, all other terms to the right

-4c=7

c=7/-4

c=-1+3/4

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