2u+40=4(u+6)

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Solution for 2u+40=4(u+6) equation: 



2u+40=4(u+6)

We move all terms to the left:

2u+40-(4(u+6))=0



We calculate terms in parentheses: -(4(u+6)), so:

4(u+6)

We multiply parentheses

4u+24

Back to the equation:

-(4u+24)



We get rid of parentheses

2u-4u-24+40=0

We add all the numbers together, and all the variables

-2u+16=0

We move all terms containing u to the left, all other terms to the right

-2u=-16

u=-16/-2

u=+8

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