6y2-41y-30=0

Solution for 6y2-41y-30=0 equation:

6y^2-41y-30=0

a = 6; b = -41; c = -30;
Δ = b2-4ac
Δ = -412-4·6·(-30)
Δ = 2401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2401}=49$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-41)-49}{2*6}=\frac{-8}{12}
=-2/3
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-41)+49}{2*6}=\frac{90}{12}
=7+1/2
$