3(c-3)=4(c-5)

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Solution for 3(c-3)=4(c-5) equation:


Simplifying
3(c + -3) = 4(c + -5)

Reorder the terms:
3(-3 + c) = 4(c + -5)
(-3 * 3 + c * 3) = 4(c + -5)
(-9 + 3c) = 4(c + -5)

Reorder the terms:
-9 + 3c = 4(-5 + c)
-9 + 3c = (-5 * 4 + c * 4)
-9 + 3c = (-20 + 4c)

Solving
-9 + 3c = -20 + 4c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-4c' to each side of the equation.
-9 + 3c + -4c = -20 + 4c + -4c

Combine like terms: 3c + -4c = -1c
-9 + -1c = -20 + 4c + -4c

Combine like terms: 4c + -4c = 0
-9 + -1c = -20 + 0
-9 + -1c = -20

Add '9' to each side of the equation.
-9 + 9 + -1c = -20 + 9

Combine like terms: -9 + 9 = 0
0 + -1c = -20 + 9
-1c = -20 + 9

Combine like terms: -20 + 9 = -11
-1c = -11

Divide each side by '-1'.
c = 11

Simplifying
c = 11

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