7(c-3)+6=3+c-18

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Solution for 7(c-3)+6=3+c-18 equation:


Simplifying
7(c + -3) + 6 = 3 + c + -18

Reorder the terms:
7(-3 + c) + 6 = 3 + c + -18
(-3 * 7 + c * 7) + 6 = 3 + c + -18
(-21 + 7c) + 6 = 3 + c + -18

Reorder the terms:
-21 + 6 + 7c = 3 + c + -18

Combine like terms: -21 + 6 = -15
-15 + 7c = 3 + c + -18

Reorder the terms:
-15 + 7c = 3 + -18 + c

Combine like terms: 3 + -18 = -15
-15 + 7c = -15 + c

Add '15' to each side of the equation.
-15 + 15 + 7c = -15 + 15 + c

Combine like terms: -15 + 15 = 0
0 + 7c = -15 + 15 + c
7c = -15 + 15 + c

Combine like terms: -15 + 15 = 0
7c = 0 + c
7c = c

Solving
7c = c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-1c' to each side of the equation.
7c + -1c = c + -1c

Combine like terms: 7c + -1c = 6c
6c = c + -1c

Combine like terms: c + -1c = 0
6c = 0

Divide each side by '6'.
c = 0

Simplifying
c = 0

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