3(c-3)-2(c-2)=120

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Solution for 3(c-3)-2(c-2)=120 equation: 


Simplifying
3(c + -3) + -2(c + -2) = 120

Reorder the terms:
3(-3 + c) + -2(c + -2) = 120
(-3 * 3 + c * 3) + -2(c + -2) = 120
(-9 + 3c) + -2(c + -2) = 120

Reorder the terms:
-9 + 3c + -2(-2 + c) = 120
-9 + 3c + (-2 * -2 + c * -2) = 120
-9 + 3c + (4 + -2c) = 120

Reorder the terms:
-9 + 4 + 3c + -2c = 120

Combine like terms: -9 + 4 = -5
-5 + 3c + -2c = 120

Combine like terms: 3c + -2c = 1c
-5 + 1c = 120

Solving
-5 + 1c = 120

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '5' to each side of the equation.
-5 + 5 + 1c = 120 + 5

Combine like terms: -5 + 5 = 0
0 + 1c = 120 + 5
1c = 120 + 5

Combine like terms: 120 + 5 = 125
1c = 125

Divide each side by '1'.
c = 125

Simplifying
c = 125

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