3(b+2)-4(b-3)=50

Solution for 3(b+2)-4(b-3)=50 equation:

Simplifying
3(b + 2) + -4(b + -3) = 50

Reorder the terms:
3(2 + b) + -4(b + -3) = 50
(2 * 3 + b * 3) + -4(b + -3) = 50
(6 + 3b) + -4(b + -3) = 50

Reorder the terms:
6 + 3b + -4(-3 + b) = 50
6 + 3b + (-3 * -4 + b * -4) = 50
6 + 3b + (12 + -4b) = 50

Reorder the terms:
6 + 12 + 3b + -4b = 50

Combine like terms: 6 + 12 = 18
18 + 3b + -4b = 50

Combine like terms: 3b + -4b = -1b
18 + -1b = 50

Solving
18 + -1b = 50

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-18' to each side of the equation.
18 + -18 + -1b = 50 + -18

Combine like terms: 18 + -18 = 0
0 + -1b = 50 + -18
-1b = 50 + -18

Combine like terms: 50 + -18 = 32
-1b = 32

Divide each side by '-1'.
b = -32

Simplifying
b = -32