3(c-1)+2=(3c+1)

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Solution for 3(c-1)+2=(3c+1) equation: 



3(c-1)+2=(3c+1)

We move all terms to the left:

3(c-1)+2-((3c+1))=0

We multiply parentheses

3c-((3c+1))-3+2=0



We calculate terms in parentheses: -((3c+1)), so:

(3c+1)

We get rid of parentheses

3c+1

Back to the equation:

-(3c+1)



We add all the numbers together, and all the variables

3c-(3c+1)-1=0

We get rid of parentheses

3c-3c-1-1=0

We add all the numbers together, and all the variables

-2!=0

There is no solution for this equation

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