3b-4=-2(b-6)

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Solution for 3b-4=-2(b-6) equation: 



3b-4=-2(b-6)

We move all terms to the left:

3b-4-(-2(b-6))=0



We calculate terms in parentheses: -(-2(b-6)), so:

-2(b-6)

We multiply parentheses

-2b+12

Back to the equation:

-(-2b+12)



We get rid of parentheses

3b+2b-12-4=0

We add all the numbers together, and all the variables

5b-16=0

We move all terms containing b to the left, all other terms to the right

5b=16

b=16/5

b=3+1/5

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