3(c+5)+5=2(c+10)+c

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Solution for 3(c+5)+5=2(c+10)+c equation: 



3(c+5)+5=2(c+10)+c

We move all terms to the left:

3(c+5)+5-(2(c+10)+c)=0

We multiply parentheses

3c-(2(c+10)+c)+15+5=0



We calculate terms in parentheses: -(2(c+10)+c), so:

2(c+10)+c

We add all the numbers together, and all the variables

c+2(c+10)

We multiply parentheses

c+2c+20

We add all the numbers together, and all the variables

3c+20

Back to the equation:

-(3c+20)



We add all the numbers together, and all the variables

3c-(3c+20)+20=0

We get rid of parentheses

3c-3c-20+20=0

We add all the numbers together, and all the variables

=0

c=0/1

c=0

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