3/4(8c-12)=-21

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Solution for 3/4(8c-12)=-21 equation: 



3/4(8c-12)=-21

We move all terms to the left:

3/4(8c-12)-(-21)=0



Domain of the equation: 4(8c-12)!=0

c∈R



We add all the numbers together, and all the variables

3/4(8c-12)+21=0

We multiply all the terms by the denominator


21*4(8c-12)+3=0

Wy multiply elements

84c(8+3=0

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