3(c+2)=3c+b

Solution for 3(c+2)=3c+b equation:

Simplifying
3(c + 2) = 3c + b

Reorder the terms:
3(2 + c) = 3c + b
(2 * 3 + c * 3) = 3c + b
(6 + 3c) = 3c + b

Reorder the terms:
6 + 3c = b + 3c

Add '-3c' to each side of the equation.
6 + 3c + -3c = b + 3c + -3c

Combine like terms: 3c + -3c = 0
6 + 0 = b + 3c + -3c
6 = b + 3c + -3c

Combine like terms: 3c + -3c = 0
6 = b + 0
6 = b

Solving
6 = b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-1b' to each side of the equation.
6 + -1b = b + -1b

Combine like terms: b + -1b = 0
6 + -1b = 0

Add '-6' to each side of the equation.
6 + -6 + -1b = 0 + -6

Combine like terms: 6 + -6 = 0
0 + -1b = 0 + -6
-1b = 0 + -6

Combine like terms: 0 + -6 = -6
-1b = -6

Divide each side by '-1'.
b = 6

Simplifying
b = 6