(3v+2)+(v+1)=v+(2v+3)

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Solution for (3v+2)+(v+1)=v+(2v+3) equation:


Simplifying
(3v + 2) + (v + 1) = v + (2v + 3)

Reorder the terms:
(2 + 3v) + (v + 1) = v + (2v + 3)

Remove parenthesis around (2 + 3v)
2 + 3v + (v + 1) = v + (2v + 3)

Reorder the terms:
2 + 3v + (1 + v) = v + (2v + 3)

Remove parenthesis around (1 + v)
2 + 3v + 1 + v = v + (2v + 3)

Reorder the terms:
2 + 1 + 3v + v = v + (2v + 3)

Combine like terms: 2 + 1 = 3
3 + 3v + v = v + (2v + 3)

Combine like terms: 3v + v = 4v
3 + 4v = v + (2v + 3)

Reorder the terms:
3 + 4v = v + (3 + 2v)

Remove parenthesis around (3 + 2v)
3 + 4v = v + 3 + 2v

Reorder the terms:
3 + 4v = 3 + v + 2v

Combine like terms: v + 2v = 3v
3 + 4v = 3 + 3v

Add '-3' to each side of the equation.
3 + -3 + 4v = 3 + -3 + 3v

Combine like terms: 3 + -3 = 0
0 + 4v = 3 + -3 + 3v
4v = 3 + -3 + 3v

Combine like terms: 3 + -3 = 0
4v = 0 + 3v
4v = 3v

Solving
4v = 3v

Solving for variable 'v'.

Move all terms containing v to the left, all other terms to the right.

Add '-3v' to each side of the equation.
4v + -3v = 3v + -3v

Combine like terms: 4v + -3v = 1v
1v = 3v + -3v

Combine like terms: 3v + -3v = 0
1v = 0

Divide each side by '1'.
v = 0

Simplifying
v = 0

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