3(c+12)=18

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Solution for 3(c+12)=18 equation: 



3(c+12)=18

We move all terms to the left:

3(c+12)-(18)=0

We multiply parentheses

3c+36-18=0

We add all the numbers together, and all the variables

3c+18=0

We move all terms containing c to the left, all other terms to the right

3c=-18

c=-18/3

c=-6

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