3(b-4)=b+8

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Solution for 3(b-4)=b+8 equation: 



3(b-4)=b+8

We move all terms to the left:

3(b-4)-(b+8)=0

We multiply parentheses

3b-(b+8)-12=0

We get rid of parentheses

3b-b-8-12=0

We add all the numbers together, and all the variables

2b-20=0

We move all terms containing b to the left, all other terms to the right

2b=20

b=20/2

b=10

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