8(4+3x)+1=53+3(x+5)

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Solution for 8(4+3x)+1=53+3(x+5) equation: 



8(4+3x)+1=53+3(x+5)

We move all terms to the left:

8(4+3x)+1-(53+3(x+5))=0

We add all the numbers together, and all the variables

8(3x+4)-(53+3(x+5))+1=0

We multiply parentheses

24x-(53+3(x+5))+32+1=0



We calculate terms in parentheses: -(53+3(x+5)), so:

53+3(x+5)

determiningTheFunctionDomain
3(x+5)+53

We multiply parentheses

3x+15+53

We add all the numbers together, and all the variables

3x+68

Back to the equation:

-(3x+68)



We add all the numbers together, and all the variables

24x-(3x+68)+33=0

We get rid of parentheses

24x-3x-68+33=0

We add all the numbers together, and all the variables

21x-35=0

We move all terms containing x to the left, all other terms to the right

21x=35

x=35/21

x=1+2/3

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