3(b-4)=2(b+7)

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Solution for 3(b-4)=2(b+7) equation: 



3(b-4)=2(b+7)

We move all terms to the left:

3(b-4)-(2(b+7))=0

We multiply parentheses

3b-(2(b+7))-12=0



We calculate terms in parentheses: -(2(b+7)), so:

2(b+7)

We multiply parentheses

2b+14

Back to the equation:

-(2b+14)



We get rid of parentheses

3b-2b-14-12=0

We add all the numbers together, and all the variables

b-26=0

We move all terms containing b to the left, all other terms to the right

b=26

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