2(b-3)=3(b+7)

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Solution for 2(b-3)=3(b+7) equation: 



2(b-3)=3(b+7)

We move all terms to the left:

2(b-3)-(3(b+7))=0

We multiply parentheses

2b-(3(b+7))-6=0



We calculate terms in parentheses: -(3(b+7)), so:

3(b+7)

We multiply parentheses

3b+21

Back to the equation:

-(3b+21)



We get rid of parentheses

2b-3b-21-6=0

We add all the numbers together, and all the variables

-1b-27=0

We move all terms containing b to the left, all other terms to the right

-b=27

b=27/-1

b=-27

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