3(b-3)(b-3)=0

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Solution for 3(b-3)(b-3)=0 equation: 



3(b-3)(b-3)=0

We multiply parentheses ..

3(+b^2-3b-3b+9)=0

We multiply parentheses

3b^2-9b-9b+27=0

We add all the numbers together, and all the variables

3b^2-18b+27=0

a = 3; b = -18; c = +27;
Δ = b2-4ac
Δ = -182-4·3·27
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$b=\frac{-b}{2a}=\frac{18}{6}=3$

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