3(b-1)-8=-1+4(2+3b)

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Solution for 3(b-1)-8=-1+4(2+3b) equation: 



3(b-1)-8=-1+4(2+3b)

We move all terms to the left:

3(b-1)-8-(-1+4(2+3b))=0

We add all the numbers together, and all the variables

3(b-1)-(-1+4(3b+2))-8=0

We multiply parentheses

3b-(-1+4(3b+2))-3-8=0



We calculate terms in parentheses: -(-1+4(3b+2)), so:

-1+4(3b+2)

determiningTheFunctionDomain
4(3b+2)-1

We multiply parentheses

12b+8-1

We add all the numbers together, and all the variables

12b+7

Back to the equation:

-(12b+7)



We add all the numbers together, and all the variables

3b-(12b+7)-11=0

We get rid of parentheses

3b-12b-7-11=0

We add all the numbers together, and all the variables

-9b-18=0

We move all terms containing b to the left, all other terms to the right

-9b=18

b=18/-9

b=-2

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