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1/3(y-9)=4y+13/3y-3
We move all terms to the left:
1/3(y-9)-(4y+13/3y-3)=0
Domain of the equation: 3(y-9)!=0
y∈R
Domain of the equation: 3y-3)!=0We get rid of parentheses
y∈R
1/3(y-9)-4y-13/3y+3=0
We calculate fractions
-4y+3y/(9y^2-81y)+(-39yy/(9y^2-81y)+3=0
We calculate fractions
We do not support eypression: y^3
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