3(b-1)-2(b+4)=5

Solution for 3(b-1)-2(b+4)=5 equation:

Simplifying
3(b + -1) + -2(b + 4) = 5

Reorder the terms:
3(-1 + b) + -2(b + 4) = 5
(-1 * 3 + b * 3) + -2(b + 4) = 5
(-3 + 3b) + -2(b + 4) = 5

Reorder the terms:
-3 + 3b + -2(4 + b) = 5
-3 + 3b + (4 * -2 + b * -2) = 5
-3 + 3b + (-8 + -2b) = 5

Reorder the terms:
-3 + -8 + 3b + -2b = 5

Combine like terms: -3 + -8 = -11
-11 + 3b + -2b = 5

Combine like terms: 3b + -2b = 1b
-11 + 1b = 5

Solving
-11 + 1b = 5

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '11' to each side of the equation.
-11 + 11 + 1b = 5 + 11

Combine like terms: -11 + 11 = 0
0 + 1b = 5 + 11
1b = 5 + 11

Combine like terms: 5 + 11 = 16
1b = 16

Divide each side by '1'.
b = 16

Simplifying
b = 16