3(u+2)-u=3(u-1)+5

Solution for 3(u+2)-u=3(u-1)+5 equation:

Simplifying
3(u + 2) + -1u = 3(u + -1) + 5

Reorder the terms:
3(2 + u) + -1u = 3(u + -1) + 5
(2 * 3 + u * 3) + -1u = 3(u + -1) + 5
(6 + 3u) + -1u = 3(u + -1) + 5

Combine like terms: 3u + -1u = 2u
6 + 2u = 3(u + -1) + 5

Reorder the terms:
6 + 2u = 3(-1 + u) + 5
6 + 2u = (-1 * 3 + u * 3) + 5
6 + 2u = (-3 + 3u) + 5

Reorder the terms:
6 + 2u = -3 + 5 + 3u

Combine like terms: -3 + 5 = 2
6 + 2u = 2 + 3u

Solving
6 + 2u = 2 + 3u

Solving for variable 'u'.

Move all terms containing u to the left, all other terms to the right.

Add '-3u' to each side of the equation.
6 + 2u + -3u = 2 + 3u + -3u

Combine like terms: 2u + -3u = -1u
6 + -1u = 2 + 3u + -3u

Combine like terms: 3u + -3u = 0
6 + -1u = 2 + 0
6 + -1u = 2

Add '-6' to each side of the equation.
6 + -6 + -1u = 2 + -6

Combine like terms: 6 + -6 = 0
0 + -1u = 2 + -6
-1u = 2 + -6

Combine like terms: 2 + -6 = -4
-1u = -4

Divide each side by '-1'.
u = 4

Simplifying
u = 4