3(b+7)=2(b-4)

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Solution for 3(b+7)=2(b-4) equation: 



3(b+7)=2(b-4)

We move all terms to the left:

3(b+7)-(2(b-4))=0

We multiply parentheses

3b-(2(b-4))+21=0



We calculate terms in parentheses: -(2(b-4)), so:

2(b-4)

We multiply parentheses

2b-8

Back to the equation:

-(2b-8)



We get rid of parentheses

3b-2b+8+21=0

We add all the numbers together, and all the variables

b+29=0

We move all terms containing b to the left, all other terms to the right

b=-29

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