64=x+2x+(4+x)

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Solution for 64=x+2x+(4+x) equation: 



64=x+2x+(4+x)

We move all terms to the left:

64-(x+2x+(4+x))=0

We add all the numbers together, and all the variables

-(x+2x+(x+4))+64=0



We calculate terms in parentheses: -(x+2x+(x+4)), so:

x+2x+(x+4)

We add all the numbers together, and all the variables

3x+(x+4)

We get rid of parentheses

3x+x+4

We add all the numbers together, and all the variables

4x+4

Back to the equation:

-(4x+4)



We get rid of parentheses

-4x-4+64=0

We add all the numbers together, and all the variables

-4x+60=0

We move all terms containing x to the left, all other terms to the right

-4x=-60

x=-60/-4

x=+15

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