3(b+44)=27

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Solution for 3(b+44)=27 equation: 



3(b+44)=27

We move all terms to the left:

3(b+44)-(27)=0

We multiply parentheses

3b+132-27=0

We add all the numbers together, and all the variables

3b+105=0

We move all terms containing b to the left, all other terms to the right

3b=-105

b=-105/3

b=-35

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