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3x(x+10)=x
We move all terms to the left:
3x(x+10)-(x)=0
We add all the numbers together, and all the variables
-1x+3x(x+10)=0
We multiply parentheses
3x^2-1x+30x=0
We add all the numbers together, and all the variables
3x^2+29x=0
a = 3; b = 29; c = 0;
Δ = b2-4ac
Δ = 292-4·3·0
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{841}=29$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(29)-29}{2*3}=\frac{-58}{6} =-9+2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(29)+29}{2*3}=\frac{0}{6} =0 $
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