3(b+2)=b-5

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Solution for 3(b+2)=b-5 equation: 



3(b+2)=b-5

We move all terms to the left:

3(b+2)-(b-5)=0

We multiply parentheses

3b-(b-5)+6=0

We get rid of parentheses

3b-b+5+6=0

We add all the numbers together, and all the variables

2b+11=0

We move all terms containing b to the left, all other terms to the right

2b=-11

b=-11/2

b=-5+1/2

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