3(u-14)+7(u-12)=14

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Solution for 3(u-14)+7(u-12)=14 equation: 



3(u-14)+7(u-12)=14

We move all terms to the left:

3(u-14)+7(u-12)-(14)=0

We multiply parentheses

3u+7u-42-84-14=0

We add all the numbers together, and all the variables

10u-140=0

We move all terms containing u to the left, all other terms to the right

10u=140

u=140/10

u=14

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