3(b+10)=6b+15

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Solution for 3(b+10)=6b+15 equation: 



3(b+10)=6b+15

We move all terms to the left:

3(b+10)-(6b+15)=0

We multiply parentheses

3b-(6b+15)+30=0

We get rid of parentheses

3b-6b-15+30=0

We add all the numbers together, and all the variables

-3b+15=0

We move all terms containing b to the left, all other terms to the right

-3b=-15

b=-15/-3

b=+5

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