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(5x+3)+(2x-4)=9-(2-3x)
We move all terms to the left:
(5x+3)+(2x-4)-(9-(2-3x))=0
We add all the numbers together, and all the variables
(5x+3)+(2x-4)-(9-(-3x+2))=0
We get rid of parentheses
5x+2x-(9-(-3x+2))+3-4=0
We calculate terms in parentheses: -(9-(-3x+2)), so:We add all the numbers together, and all the variables
9-(-3x+2)
determiningTheFunctionDomain -(-3x+2)+9
We get rid of parentheses
3x-2+9
We add all the numbers together, and all the variables
3x+7
Back to the equation:
-(3x+7)
7x-(3x+7)-1=0
We get rid of parentheses
7x-3x-7-1=0
We add all the numbers together, and all the variables
4x-8=0
We move all terms containing x to the left, all other terms to the right
4x=8
x=8/4
x=2
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