3(a-5)=2(a+3)

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Solution for 3(a-5)=2(a+3) equation: 



3(a-5)=2(a+3)

We move all terms to the left:

3(a-5)-(2(a+3))=0

We multiply parentheses

3a-(2(a+3))-15=0



We calculate terms in parentheses: -(2(a+3)), so:

2(a+3)

We multiply parentheses

2a+6

Back to the equation:

-(2a+6)



We get rid of parentheses

3a-2a-6-15=0

We add all the numbers together, and all the variables

a-21=0

We move all terms containing a to the left, all other terms to the right

a=21

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