(10x-40=5x+5)

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Solution for (10x-40=5x+5) equation: 



(10x-40=5x+5)

We move all terms to the left:

(10x-40-(5x+5))=0



We calculate terms in parentheses: +(10x-40-(5x+5)), so:

10x-40-(5x+5)

determiningTheFunctionDomain
10x-(5x+5)-40

We get rid of parentheses

10x-5x-5-40

We add all the numbers together, and all the variables

5x-45

Back to the equation:

+(5x-45)



We get rid of parentheses

5x-45=0

We move all terms containing x to the left, all other terms to the right

5x=45

x=45/5

x=9

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