3(a-4)=12a-6(2-a)

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Solution for 3(a-4)=12a-6(2-a) equation: 



3(a-4)=12a-6(2-a)

We move all terms to the left:

3(a-4)-(12a-6(2-a))=0

We add all the numbers together, and all the variables

3(a-4)-(12a-6(-1a+2))=0

We multiply parentheses

3a-(12a-6(-1a+2))-12=0



We calculate terms in parentheses: -(12a-6(-1a+2)), so:

12a-6(-1a+2)

We multiply parentheses

12a+6a-12

We add all the numbers together, and all the variables

18a-12

Back to the equation:

-(18a-12)



We get rid of parentheses

3a-18a+12-12=0

We add all the numbers together, and all the variables

-15a=0

a=0/-15

a=0

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