3(a-3)=2(4+a)

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Solution for 3(a-3)=2(4+a) equation: 



3(a-3)=2(4+a)

We move all terms to the left:

3(a-3)-(2(4+a))=0

We add all the numbers together, and all the variables

3(a-3)-(2(a+4))=0

We multiply parentheses

3a-(2(a+4))-9=0



We calculate terms in parentheses: -(2(a+4)), so:

2(a+4)

We multiply parentheses

2a+8

Back to the equation:

-(2a+8)



We get rid of parentheses

3a-2a-8-9=0

We add all the numbers together, and all the variables

a-17=0

We move all terms containing a to the left, all other terms to the right

a=17

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