3(a-10)+4a=-2(10-5a)-16

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Solution for 3(a-10)+4a=-2(10-5a)-16 equation: 



3(a-10)+4a=-2(10-5a)-16

We move all terms to the left:

3(a-10)+4a-(-2(10-5a)-16)=0

We add all the numbers together, and all the variables

3(a-10)+4a-(-2(-5a+10)-16)=0

We add all the numbers together, and all the variables

4a+3(a-10)-(-2(-5a+10)-16)=0

We multiply parentheses

4a+3a-(-2(-5a+10)-16)-30=0



We calculate terms in parentheses: -(-2(-5a+10)-16), so:

-2(-5a+10)-16

We multiply parentheses

10a-20-16

We add all the numbers together, and all the variables

10a-36

Back to the equation:

-(10a-36)



We add all the numbers together, and all the variables

7a-(10a-36)-30=0

We get rid of parentheses

7a-10a+36-30=0

We add all the numbers together, and all the variables

-3a+6=0

We move all terms containing a to the left, all other terms to the right

-3a=-6

a=-6/-3

a=+2

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