3(a-10)+4(a-19)=13

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Solution for 3(a-10)+4(a-19)=13 equation: 



3(a-10)+4(a-19)=13

We move all terms to the left:

3(a-10)+4(a-19)-(13)=0

We multiply parentheses

3a+4a-30-76-13=0

We add all the numbers together, and all the variables

7a-119=0

We move all terms containing a to the left, all other terms to the right

7a=119

a=119/7

a=17

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