3(a+4)+2=2(a-1)+a+19

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Solution for 3(a+4)+2=2(a-1)+a+19 equation: 



3(a+4)+2=2(a-1)+a+19

We move all terms to the left:

3(a+4)+2-(2(a-1)+a+19)=0

We multiply parentheses

3a-(2(a-1)+a+19)+12+2=0



We calculate terms in parentheses: -(2(a-1)+a+19), so:

2(a-1)+a+19

We add all the numbers together, and all the variables

a+2(a-1)+19

We multiply parentheses

a+2a-2+19

We add all the numbers together, and all the variables

3a+17

Back to the equation:

-(3a+17)



We add all the numbers together, and all the variables

3a-(3a+17)+14=0

We get rid of parentheses

3a-3a-17+14=0

We add all the numbers together, and all the variables

-3!=0

There is no solution for this equation

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