3(a+3)+3(a-1)=5(a+5)

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Solution for 3(a+3)+3(a-1)=5(a+5) equation: 



3(a+3)+3(a-1)=5(a+5)

We move all terms to the left:

3(a+3)+3(a-1)-(5(a+5))=0

We multiply parentheses

3a+3a-(5(a+5))+9-3=0



We calculate terms in parentheses: -(5(a+5)), so:

5(a+5)

We multiply parentheses

5a+25

Back to the equation:

-(5a+25)



We add all the numbers together, and all the variables

6a-(5a+25)+6=0

We get rid of parentheses

6a-5a-25+6=0

We add all the numbers together, and all the variables

a-19=0

We move all terms containing a to the left, all other terms to the right

a=19

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