If it's not what You are looking for type in the equation solver your own equation and let us solve it.
10x^2+2x=9
We move all terms to the left:
10x^2+2x-(9)=0
a = 10; b = 2; c = -9;
Δ = b2-4ac
Δ = 22-4·10·(-9)
Δ = 364
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{364}=\sqrt{4*91}=\sqrt{4}*\sqrt{91}=2\sqrt{91}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2\sqrt{91}}{2*10}=\frac{-2-2\sqrt{91}}{20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2\sqrt{91}}{2*10}=\frac{-2+2\sqrt{91}}{20} $
| 18+10x+3x=106-55 | | 3^x*5^(2/x)=75 | | 0.15x3+18.7x2-4975.5=0 | | (X)+(x+1)+(x+2)=153 | | (6x+5)(4x-1)=0 | | 5x^2+40x+56=0 | | 90x-5=5 | | 10x+5=25=x | | 2(x+2+x-8)=180 | | 3+3.6x^-1+0.6x^-2=0 | | -15z+21+5z=-19 | | 5p2=5 | | 7-(5p-13)=-25 | | 2x^2-27x-27=0 | | 9(x+1)=3(5x+1)-12 | | 6(2x+4)-24=12x | | 120-7x=150-9x | | 92+16x=104+13x | | 180-20x=140-16x | | -2(v-4)=4v+32 | | -2y-46=-5(y+5) | | 7(w+7)=-4w-39 | | -v+187=87 | | -w+46=282 | | 192=142-v | | 065=0.5c | | 3/5p=1 | | 13-9x-5x(2)=0 | | 7a+2=4a+7 | | 3(a-5)-a(a-2)=0 | | 14(5/7y+3/2)-8(7/4y-13/8)=11/2 | | 11k+13-(8k-5)+3k=0 |