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3(a-5)-a(a-2)=0
We multiply parentheses
-a^2+3a+2a-15=0
We add all the numbers together, and all the variables
-1a^2+5a-15=0
a = -1; b = 5; c = -15;
Δ = b2-4ac
Δ = 52-4·(-1)·(-15)
Δ = -35
Delta is less than zero, so there is no solution for the equation
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