3(a+2)=10-a

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Solution for 3(a+2)=10-a equation: 



3(a+2)=10-a

We move all terms to the left:

3(a+2)-(10-a)=0

We add all the numbers together, and all the variables

3(a+2)-(-1a+10)=0

We multiply parentheses

3a-(-1a+10)+6=0

We get rid of parentheses

3a+1a-10+6=0

We add all the numbers together, and all the variables

4a-4=0

We move all terms containing a to the left, all other terms to the right

4a=4

a=4/4

a=1

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