1/2(10f-6)+2f=11

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Solution for 1/2(10f-6)+2f=11 equation: 



1/2(10f-6)+2f=11

We move all terms to the left:

1/2(10f-6)+2f-(11)=0



Domain of the equation: 2(10f-6)!=0

f∈R



We add all the numbers together, and all the variables

2f+1/2(10f-6)-11=0

We multiply all the terms by the denominator


2f*2(10f-6)-11*2(10f-6)+1=0

Wy multiply elements

4f^2(1-22f(1+1=0

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