3(a+2)-5=2(a+1)

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Solution for 3(a+2)-5=2(a+1) equation: 



3(a+2)-5=2(a+1)

We move all terms to the left:

3(a+2)-5-(2(a+1))=0

We multiply parentheses

3a-(2(a+1))+6-5=0



We calculate terms in parentheses: -(2(a+1)), so:

2(a+1)

We multiply parentheses

2a+2

Back to the equation:

-(2a+2)



We add all the numbers together, and all the variables

3a-(2a+2)+1=0

We get rid of parentheses

3a-2a-2+1=0

We add all the numbers together, and all the variables

a-1=0

We move all terms containing a to the left, all other terms to the right

a=1

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