3(a+10)=27-(3a-9)

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Solution for 3(a+10)=27-(3a-9) equation: 



3(a+10)=27-(3a-9)

We move all terms to the left:

3(a+10)-(27-(3a-9))=0

We multiply parentheses

3a-(27-(3a-9))+30=0



We calculate terms in parentheses: -(27-(3a-9)), so:

27-(3a-9)

determiningTheFunctionDomain
-(3a-9)+27

We get rid of parentheses

-3a+9+27

We add all the numbers together, and all the variables

-3a+36

Back to the equation:

-(-3a+36)



We get rid of parentheses

3a+3a-36+30=0

We add all the numbers together, and all the variables

6a-6=0

We move all terms containing a to the left, all other terms to the right

6a=6

a=6/6

a=1

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