3(9x-41)=3(3x-5)

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Solution for 3(9x-41)=3(3x-5) equation:



3(9x-41)=3(3x-5)
We move all terms to the left:
3(9x-41)-(3(3x-5))=0
We multiply parentheses
27x-(3(3x-5))-123=0
We calculate terms in parentheses: -(3(3x-5)), so:
3(3x-5)
We multiply parentheses
9x-15
Back to the equation:
-(9x-15)
We get rid of parentheses
27x-9x+15-123=0
We add all the numbers together, and all the variables
18x-108=0
We move all terms containing x to the left, all other terms to the right
18x=108
x=108/18
x=6

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