x(x+2)=(x-3)2

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Solution for x(x+2)=(x-3)2 equation: 



x(x+2)=(x-3)2

We move all terms to the left:

x(x+2)-((x-3)2)=0

We multiply parentheses

x^2+2x-((x-3)2)=0



We calculate terms in parentheses: -((x-3)2), so:

(x-3)2

We multiply parentheses

2x-6

Back to the equation:

-(2x-6)



We get rid of parentheses

x^2+2x-2x+6=0

We add all the numbers together, and all the variables

x^2+6=0

a = 1; b = 0; c = +6;
Δ = b2-4ac
Δ = 02-4·1·6
Δ = -24
Delta is less than zero, so there is no solution for the equation

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