3(9+z)=48

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Solution for 3(9+z)=48 equation: 



3(9+z)=48

We move all terms to the left:

3(9+z)-(48)=0

We add all the numbers together, and all the variables

3(z+9)-48=0

We multiply parentheses

3z+27-48=0

We add all the numbers together, and all the variables

3z-21=0

We move all terms containing z to the left, all other terms to the right

3z=21

z=21/3

z=7

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